The observation that should be seen as most promising for developing a testable hypothesis that helps determine the connection between organisms farming and biodiversity is:
C. Twenty-one different wildflower species were observed in a meadow on a land located within an organic farm.
This observation suggests that the organic farming practices on the land may be supporting a greater diversity of plant species, which in turn could support a greater diversity of other organisms.
Which observation should the scientists see is most promising for developing a testable hypothesis that helps determine the connection between organisms farming and biodiversity
A. 12 different fish species were observed in a small pond on land located within an organization farm upon your a conventional farming only three species.
B. An enormous number of starlings were observed in an orchard adjacent to organic farmland. Thousands of starlings, were estimated to be observed.
C. Twenty-one different wildflower species were observed in a meadow on a land located within an organic farm
5 answers
Y= x - 7
X= 4
Y=
-3
4
3
X= 4
Y=
-3
4
3
If the equation is given as y = x - 7, we can substitute the value of x into the equation to find the corresponding value of y.
Given x = 4:
y = 4 - 7 = -3
So, when x = 4, y = -3.
Similarly, if x = 3:
y = 3 - 7 = -4
So, when x = 3, y = -4.
And if x = -3:
y = -3 - 7 = -10
So, when x = -3, y = -10.
Given x = 4:
y = 4 - 7 = -3
So, when x = 4, y = -3.
Similarly, if x = 3:
y = 3 - 7 = -4
So, when x = 3, y = -4.
And if x = -3:
y = -3 - 7 = -10
So, when x = -3, y = -10.
X + 5y = 28
2x + 3y = 21
Solve for x and y
X=8, y= 4
X=6, y=1
X=3, y=5
2x + 3y = 21
Solve for x and y
X=8, y= 4
X=6, y=1
X=3, y=5
To solve the system of equations:
1) X + 5y = 28
2) 2x + 3y = 21
You can use either the substitution method or the elimination method. Let's use the elimination method.
Multiply equation 1 by 2, and equation 2 by -1 to eliminate x:
1) 2(x + 5y) = 2(28) => 2x + 10y = 56
2) -1(2x + 3y) = -1(21) => -2x - 3y = -21
Adding the two equations together eliminates x:
2x + 10y -2x - 3y = 56 - 21
7y = 35
y = 35/7
y = 5
Now substitute the value of y back into equation 1:
x + 5(5) = 28
x + 25 = 28
x = 28 - 25
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 5.
1) X + 5y = 28
2) 2x + 3y = 21
You can use either the substitution method or the elimination method. Let's use the elimination method.
Multiply equation 1 by 2, and equation 2 by -1 to eliminate x:
1) 2(x + 5y) = 2(28) => 2x + 10y = 56
2) -1(2x + 3y) = -1(21) => -2x - 3y = -21
Adding the two equations together eliminates x:
2x + 10y -2x - 3y = 56 - 21
7y = 35
y = 35/7
y = 5
Now substitute the value of y back into equation 1:
x + 5(5) = 28
x + 25 = 28
x = 28 - 25
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 5.