To determine which object would reach 100 feet in the least amount of time, we need to calculate the speed of each object and compare them.
The speed of an object is determined by dividing the distance traveled by the time taken.
Object A travels a horizontal distance of 3 feet and a vertical distance of 6 feet. Using the Pythagorean theorem, we can calculate the total distance traveled:
distance = sqrt((3^2) + (6^2)) = sqrt(9 + 36) = sqrt(45) ≈ 6.71 feet
Object B travels a horizontal distance of 6 feet and a vertical distance of 6 feet. Using the Pythagorean theorem, we can calculate the total distance traveled:
distance = sqrt((6^2) + (6^2)) = sqrt(36 + 36) = sqrt(72) ≈ 8.49 feet
Object C travels a horizontal distance of 6 feet and a vertical distance of 3 feet. Using the Pythagorean theorem, we can calculate the total distance traveled:
distance = sqrt((6^2) + (3^2)) = sqrt(36 + 9) = sqrt(45) ≈ 6.71 feet
Now, we can calculate the speed of each object by dividing the total distance by the time taken. However, we don't have the time information in the given options, so we cannot determine which object would reach 100 feet in the least amount of time.
Which object would reach 100 feet in the least amount of time?
A: (3,6)
B: (6,6)
C: (6,3)
9 answers
Y = distance (feet)
X = time (seconds)
X = time (seconds)
Apologies for the confusion. To determine which object would reach 100 feet in the least amount of time, we need to calculate the speed of each object and compare them.
Let's assume that the horizontal distance remains constant for all objects:
Object A: X = 3 feet
Object B: X = 6 feet
Object C: X = 6 feet
Now, we can calculate the time taken for each object to reach a vertical distance of 100 feet using the equation:
time (seconds) = distance (feet) / speed (feet per second)
For object A:
time_A = 100 feet / 6 feet per second ≈ 16.67 seconds
For object B:
time_B = 100 feet / 6 feet per second ≈ 16.67 seconds
For object C:
time_C = 100 feet / 3 feet per second ≈ 33.33 seconds
From the calculations, we can see that both object A and object B would reach 100 feet in the same amount of time, which is approximately 16.67 seconds. Object C would take the longest time, approximately 33.33 seconds.
Therefore, object A and object B would reach 100 feet in the least amount of time, with object C taking the longest.
Let's assume that the horizontal distance remains constant for all objects:
Object A: X = 3 feet
Object B: X = 6 feet
Object C: X = 6 feet
Now, we can calculate the time taken for each object to reach a vertical distance of 100 feet using the equation:
time (seconds) = distance (feet) / speed (feet per second)
For object A:
time_A = 100 feet / 6 feet per second ≈ 16.67 seconds
For object B:
time_B = 100 feet / 6 feet per second ≈ 16.67 seconds
For object C:
time_C = 100 feet / 3 feet per second ≈ 33.33 seconds
From the calculations, we can see that both object A and object B would reach 100 feet in the same amount of time, which is approximately 16.67 seconds. Object C would take the longest time, approximately 33.33 seconds.
Therefore, object A and object B would reach 100 feet in the least amount of time, with object C taking the longest.
A's feet is 6
Apologies for my mistake. With object A travelling a horizontal distance of 6 feet, let's calculate the time taken for each object to reach a vertical distance of 100 feet:
For object A:
time_A = 100 feet / 6 feet per second ≈ 16.67 seconds
For object B:
time_B = 100 feet / 6 feet per second ≈ 16.67 seconds
For object C:
time_C = 100 feet / 3 feet per second ≈ 33.33 seconds
From the calculations, both object A and object B would reach 100 feet in the same amount of time, which is approximately 16.67 seconds. Object C would take the longest time, about 33.33 seconds.
Therefore, object A and object B would reach 100 feet in the least amount of time, with object C taking the longest.
For object A:
time_A = 100 feet / 6 feet per second ≈ 16.67 seconds
For object B:
time_B = 100 feet / 6 feet per second ≈ 16.67 seconds
For object C:
time_C = 100 feet / 3 feet per second ≈ 33.33 seconds
From the calculations, both object A and object B would reach 100 feet in the same amount of time, which is approximately 16.67 seconds. Object C would take the longest time, about 33.33 seconds.
Therefore, object A and object B would reach 100 feet in the least amount of time, with object C taking the longest.
Which two ratios form a proportion?(1 point)
Responses
420 and 254 over 20 and 2 fifths
420 and 154 over 20 and 1 fifth
204 and 1520 fourths and 1 fifth
204 and 25
Responses
420 and 254 over 20 and 2 fifths
420 and 154 over 20 and 1 fifth
204 and 1520 fourths and 1 fifth
204 and 25
The two ratios that form a proportion are:
420 and 154 over 20 and 1 fifth
420 and 154 over 20 and 1 fifth
Which two ratios form a proportion?(1 point)
Responses
4/20 and 2/5
4 over 20 and 2 fifths
4/20 and 1/5
4 over 20 and 1 fifth
20/4 and 15/20
fourths and 1 fifth
20/4 and 2/5
Responses
4/20 and 2/5
4 over 20 and 2 fifths
4/20 and 1/5
4 over 20 and 1 fifth
20/4 and 15/20
fourths and 1 fifth
20/4 and 2/5
The two ratios that form a proportion are:
4/20 and 1/5
4 over 20 and 1 fifth
4/20 and 1/5
4 over 20 and 1 fifth
1 answer