The simplest way to solve the system would be to substitute the value of y from the first equation into the second equation.
Given that y = (1/2)x, we can substitute this into the second equation to get:
2x + 3(1/2)x = 28
Simplifying this equation gives:
2x + (3/2)x = 28
Combining like terms:
(4/2)x + (3/2)x = 28
(7/2)x = 28
To isolate x, we multiply both sides of the equation by the reciprocal of (7/2), which is (2/7):
[(7/2)x][(2/7)] = 28 [(2/7)]
x = 8
Now, we can substitute this value of x back into the first equation to find y:
y = (1/2)(8)
y = 4
Therefore, the solution to the system is x = 8 and y = 4.
Which method would be the simplest way to solve the system?
y = one-halfx
2x + 3y = 28
1 answer