Which line is steeper, 5x-5y-5=0 or 3x+4y-2=0?

1 answer

To determine which line is steeper, we need to compare the slopes of the two lines.

The slope-intercept form of a line is y = mx + b, where m represents the slope of the line.

For the first line, 5x - 5y - 5 = 0, we need to rewrite it in slope-intercept form by isolating y:

5x - 5y - 5 = 0
-5y = -5x + 5
y = x - 1

The slope of this line is 1.

For the second line, 3x + 4y - 2 = 0, we need to rewrite it in slope-intercept form by isolating y:

4y = -3x + 2
y = -3/4x + 1/2

The slope of this line is -3/4.

Comparing the two slopes, we can see that the first line (y = x - 1) has a slope of 1, while the second line (y = -3/4x + 1/2) has a slope of -3/4. Therefore, the first line is steeper.