To find a line perpendicular to the line \( y = -\frac{7}{4}x \), we first need to determine the slope of the given line. The slope of the line is \(-\frac{7}{4}\).
For two lines to be perpendicular, the product of their slopes must equal \(-1\). Thus, the slope \( m \) of the line we’re looking for can be found using:
\[ m \cdot \left(-\frac{7}{4}\right) = -1 \]
Solving for \( m \):
\[ m = \frac{4}{7} \]
Now, we have the slope of the perpendicular line, which is \( \frac{4}{7} \).
Next, we’ll use the point-slope form of the equation of a line to find the equation of the line with this slope that passes through the point \( (-7, 5) \):
\[ y - y_1 = m(x - x_1) \]
Substituting in \( m = \frac{4}{7} \), \( x_1 = -7 \), and \( y_1 = 5 \):
\[ y - 5 = \frac{4}{7}(x + 7) \]
Now, we can simplify this equation:
\[ y - 5 = \frac{4}{7}x + 4 \] \[ y = \frac{4}{7}x + 9 \]
So the perpendicular line that goes through the point \((-7, 5)\) is
\[ y = \frac{4}{7}x + 9 \]
The correct response is:
y = \(\frac{4}{7}\)x + 9.