To solve the expression \(\frac{2^{-3}}{3^{-2}}\), we can first rewrite it:
\[ \frac{2^{-3}}{3^{-2}} = 2^{-3} \cdot 3^{2} \]
Next, we simplify each part:
\[ 2^{-3} = \frac{1}{2^3} = \frac{1}{8} \] \[ 3^{2} = 9 \]
Now, we combine these results:
\[ 2^{-3} \cdot 3^{2} = \frac{1}{8} \cdot 9 = \frac{9}{8} \]
Thus, the value of \(\frac{2^{-3}}{3^{-2}}\) is \(\frac{9}{8}\).
The correct answer from the provided options is:
D. \(\frac{9}{8}\).