To solve the inequality \( 12x + 3 \leq 5 \), follow these steps:
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Subtract 3 from both sides: \[ 12x + 3 - 3 \leq 5 - 3 \] \[ 12x \leq 2 \]
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Divide both sides by 12: \[ x \leq \frac{2}{12} \] \[ x \leq \frac{1}{6} \]
The solution to the inequality is: \[ x \leq \frac{1}{6} \]