replace x with 15
Looks like #4 to me
nothing has been said about the domain. And anyway, f(15) would be in the range.
Which is the correct way to evaluate f(15) for the function f(x)=2(x+3)?
1. Since f(15) means the output value is 15, the function evaluates to f(15)=15.
2. Since f(15) is not within the domain of the function, it cannot be evaluated.
3. Start by letting 2(x+3)=15, then solve for x. When solved, the answer is x=4.5.
4. Start by substituting 15 for x. Then, simplify to get f(15)=36.
2 sounds good i think??
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