which is the correct balanced equation for a given titration process, (a) or (b)?
a) 6H+ + 2MnO4- + 3H2O2 -> 4O2 + 2Mn2+ + 6H2O
b) 6H+ + 2MnO4- + 5H2O2 -> 5O2 + 2Mn2+ + 8H2O
Process:
Make a solution in a 100mL volumetric flask using 1g of NaBO3*4H2O, 20mL of 1M H2SO4, and distilled water. Using this solution take 10mL of it and place in a beaker and add 20mL of 1M H2SO4. Now take the 30mL solution beaker and titrate with 0.0103M of KMnO4 to the endpoint. (endpoint found to be ~29mL)The H2O2 come from NaBO3*4H2O in acidic solution.
**I think the answer is (b) because this is an acidic solution, but I'm not sure. Can you please tell me the error of my ways if I am incorrect?
Also, is there a way to find this out using calculations or something? (stoichiometry perhaps or another way like?) I think knowing the theory behind this would be helpful in the future. please help me, I'd love your feedback.
** the oxygen is evolved from the H2O2, yes?