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Question

Which is NOT true about the mathematical statement
?

The two fractions are equivalent.

The value of the question mark is the product of the part
100 divided by the percentage.

One of the cross-products is part
percent.

You can use this mathematical statement to solve for an unknown whole value.

Answer 1

To determine which statement is NOT true about the mathematical statement involving fractions and percentages, let's analyze them one by one:

1. The two fractions are equivalent.
   This statement suggests that the fractions being compared (like a part over a whole and the percentage) are equal. In many cases involving fractions and percentages, this is accurate if they accurately represent the same relationship.

2. The value of the question mark is the product of the part 100 divided by the percentage.
   This statement can be seen as an expression of how to find the whole when given a part and a percentage. If you have a part (let's say \( x \)) and a percentage (let's say \( p% \)), then the relationship can be expressed as \( x = \frac{p}{100} \times \text{Whole} \), which implies \( \text{Whole} = \frac{x \times 100}{p} \). Therefore, if we denote the value of the question mark as the whole, this statement holds true.

3. One of the cross-products is part percent.
   Cross-multiplication usually applies to fractions. If we have two fractions \( \frac{part}{whole} = \frac{percent}{100} \), cross-multiplying gives us \( part \cdot 100 = percent \cdot whole \), so this statement is likely misleading; the term "part percent" is not a typical concept in cross-multiplication, as percentages are generally related to parts and wholes distinctly rather than as a single term.

4. You can use this mathematical statement to solve for an unknown whole value.
   This statement is true. Using the relationship between parts, percentages, and wholes, you can easily solve for the unknown whole provided you have the values of the part and the percentage.

Based on the above analysis, the statement that is NOT true appears to be "One of the cross-products is part percent." This is misleading or incorrect since it does not align with standard definitions and usage of terms in the context of fractions and percentages.

Answer 2

Why do metal ions giive up electrons and what type of ion occurs when they give up these electrons?

Answer 3

Metal ions give up electrons due to their atomic structure and the energy considerations associated with their electron configurations. Here’s a breakdown of why they do this:

Reasons Why Metal Ions Give Up Electrons:

1. Electron Configuration:
   Metals typically have a small number of electrons in their outermost electron shell, which makes them more likely to lose these outer electrons to achieve a stable electron configuration. Many metals follow the octet rule, where they are more stable when they tend to have eight electrons in their valence shell. For metals, this often means losing electrons to reach a noble gas configuration.

2. Energy Considerations:
   Removing electrons from metal ions requires energy (ionization energy), but for many metals, the energy released from the resultant electron arrangement (due to increased stability) outweighs the ionization energy. The process of losing electrons leads to the formation of more stable electron configurations.

3. Metallic Character:
   Metals have a tendency to lose electrons because they have lower electronegativities and weaker hold on their valence electrons compared to nonmetals. As a result, they readily participate in reactions where they can lose electrons.

Type of Ion Formed:

When metal ions give up electrons, they form cations. Cations are positively charged ions that are created when an atom loses one or more electrons. The loss of negatively charged electrons results in a net positive charge for the ion.

For example:

• Sodium (Na), when it loses one electron, forms a sodium cation:
  \[ \text{Na} \rightarrow \text{Na}^+ + e^- \]

• Magnesium (Mg), when it loses two electrons, forms a magnesium cation:
  \[ \text{Mg} \rightarrow \text{Mg}^{2+} + 2e^- \]

In summary, metal ions give up electrons to achieve a more stable electron configuration, resulting in the formation of positively charged ions called cations.

Answer 4

Give one sentence

Answer 5

Metal ions give up electrons to achieve a stable electron configuration, resulting in the formation of positively charged ions called cations.

Answer 6

Rephrase this sentence in 5th grade sentence

Answer 7

Metal ions lose electrons to become more stable, which makes them positively charged ions called cations.