Neon has a configuration of:
1s2 2s2 2p6
So do you find one of the choices have electrons that are out of place?
Which is not a ground state electron configuration?
A. 1s2
B. 1s2 2p1
C. 1s2 2s2
D. 1s2 2s2 2p1
5 answers
Yes 1s2 2s2 2p1,I am right?
Electrons are filled in order of the orbitals such that there is least energy, or the ground state.
The first to be filled are:
1s2 2s2 2p6 (configuration for neon).
If they are filled out of order, it will be in the excited state (not ground state).
So for
H 1s1
He 1s2
Li 1s2 2s1
Be 1s2 2s2
B 1s2 2s2 2p1
...
Ne 1s2 2s2 2p6
So can you now find one of the choices where the orbitals are filled "out of turn", or not in the ground state?
To help you understand, and as a reference, you can look at:
http://www.mikeblaber.org/oldwine/chm1045/notes/Struct/EPeriod/Struct09.htm
The first to be filled are:
1s2 2s2 2p6 (configuration for neon).
If they are filled out of order, it will be in the excited state (not ground state).
So for
H 1s1
He 1s2
Li 1s2 2s1
Be 1s2 2s2
B 1s2 2s2 2p1
...
Ne 1s2 2s2 2p6
So can you now find one of the choices where the orbitals are filled "out of turn", or not in the ground state?
To help you understand, and as a reference, you can look at:
http://www.mikeblaber.org/oldwine/chm1045/notes/Struct/EPeriod/Struct09.htm
1s2 2p1 is that right? Thank you so much!
I know that 1s2 2s2 2p1 is the excited state of 1s2 2s2 but then 1s2 2p1 its orbital are filled out of turn. So I am kinda confused about it because you said that if its excited state then that means its not ground state and if the orbitals are filled out of turn then that's not in the ground state too. So does it mean that b and d are both not in ground state?