Which is more concentrated vinegar ( 5%. {W/V }acetic acid) or 1 M acetic acid.
3 answers
1 M acetic acid is more concentrated than vinegar (5% W/V acetic acid).
can u solve it
Yes, I can explain it.
The concentration of vinegar is given in terms of mass/volume percentage i.e., 5% (W/V) acetic acid means 5 grams of acetic acid in 100 ml of vinegar. On the other hand, 1 M acetic acid means 1 mole of acetic acid in 1 liter of solution.
To compare the concentration of both solutions, we need to convert them to the same unit. We can convert 5% (W/V) acetic acid to molarity using the formula:
Molarity = (Mass of solute in grams / Molar mass of solute) / Volume of solution in liters
The molar mass of acetic acid is 60.05 g/mol. Therefore, the molarity of 5% (W/V) acetic acid solution can be calculated as:
Molarity = (5 g / 60.05 g/mol) / (100 ml / 1000 ml/L) = 0.83 M
This means that 1 M acetic acid solution is more concentrated than 5% (W/V) acetic acid solution.
The concentration of vinegar is given in terms of mass/volume percentage i.e., 5% (W/V) acetic acid means 5 grams of acetic acid in 100 ml of vinegar. On the other hand, 1 M acetic acid means 1 mole of acetic acid in 1 liter of solution.
To compare the concentration of both solutions, we need to convert them to the same unit. We can convert 5% (W/V) acetic acid to molarity using the formula:
Molarity = (Mass of solute in grams / Molar mass of solute) / Volume of solution in liters
The molar mass of acetic acid is 60.05 g/mol. Therefore, the molarity of 5% (W/V) acetic acid solution can be calculated as:
Molarity = (5 g / 60.05 g/mol) / (100 ml / 1000 ml/L) = 0.83 M
This means that 1 M acetic acid solution is more concentrated than 5% (W/V) acetic acid solution.