Which is a rational number
11
15
16
18
11 answers
All of the given numbers are rational numbers because they can be expressed as fractions.
Squared numbers
Squared numbers are numbers that have been multiplied by themselves.
Some examples of squared numbers are:
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100
So, all numbers from 1 to 10 have squared numbers.
Some examples of squared numbers are:
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100
So, all numbers from 1 to 10 have squared numbers.
NO, which number is rational
sqrt11
sqrt15
sqrt16
sqrt18
sqrt11
sqrt15
sqrt16
sqrt18
Out of the given numbers, √16 is a rational number. This is because √16 is equal to 4, which can be expressed as the fraction 4/1.
On the other hand, √11, √15, and √18 are irrational numbers. This means they cannot be expressed as fractions and have non-repeating, non-terminating decimal representations.
On the other hand, √11, √15, and √18 are irrational numbers. This means they cannot be expressed as fractions and have non-repeating, non-terminating decimal representations.
write 0.1717... as a fraction
To write 0.1717... as a fraction, we can use the concept of repeating decimals.
Let's denote x = 0.1717....
To eliminate the repeating part, we can multiply both sides of the equation by 100 (or a power of 10) to shift the decimal point:
100x = 17.1717...
Now, we subtract the two equations to eliminate the repeating part:
100x - x = 17.1717... - 0.1717...
99x = 17
Dividing both sides by 99:
x = 17/99
Therefore, the fraction form of 0.1717... is 17/99.
Let's denote x = 0.1717....
To eliminate the repeating part, we can multiply both sides of the equation by 100 (or a power of 10) to shift the decimal point:
100x = 17.1717...
Now, we subtract the two equations to eliminate the repeating part:
100x - x = 17.1717... - 0.1717...
99x = 17
Dividing both sides by 99:
x = 17/99
Therefore, the fraction form of 0.1717... is 17/99.
Find the slope of the lime containing (3,9)and (5,-3)
To find the slope of a line passing through two points, you can use the formula:
slope = (y2 - y1) / (x2 - x1)
Given the points (3,9) and (5,-3), we can assign the coordinates as follows:
x1 = 3
y1 = 9
x2 = 5
y2 = -3
Substituting these values into the slope formula:
slope = (-3 - 9) / (5 - 3)
slope = (-12) / (2)
slope = -6
Therefore, the slope of the line passing through the points (3,9) and (5,-3) is -6.
slope = (y2 - y1) / (x2 - x1)
Given the points (3,9) and (5,-3), we can assign the coordinates as follows:
x1 = 3
y1 = 9
x2 = 5
y2 = -3
Substituting these values into the slope formula:
slope = (-3 - 9) / (5 - 3)
slope = (-12) / (2)
slope = -6
Therefore, the slope of the line passing through the points (3,9) and (5,-3) is -6.
Graph this information
Andrew started at home. For the first 15 minutes he traveled at a constant speed and traveled a total of 4 miles. For the next 10 minute he rested. Andrew then rode his bike home which took a total of 20 minutes.
Andrew started at home. For the first 15 minutes he traveled at a constant speed and traveled a total of 4 miles. For the next 10 minute he rested. Andrew then rode his bike home which took a total of 20 minutes.
To graph Andrew's journey, we can plot the time on the x-axis and the distance from home on the y-axis.
First, Andrew travels a total of 4 miles in the first 15 minutes at a constant speed. So, we can plot a point at (15, 4) on the graph.
Then, Andrew rests for 10 minutes. We can represent this as a horizontal line segment on the graph from (15, 4) to (25, 4) to denote that he remains at the same distance from home during this period.
After resting, Andrew rides his bike home in the next 20 minutes. Since the total journey from home to a destination and back home takes 20 minutes, we can represent this as a diagonal line segment on the graph from (25, 4) to (45, 0) to show that he returns to his starting point.
The graph should show a diagonal line segment from (0,0) to (15,4), a horizontal line segment from (15,4) to (25,4), and another diagonal line segment from (25,4) to (45,0).
Here's a visual representation of the graph:
|
5 |
|
|
4 ---•--------•----------•--
0 15 25 45
minutes
Note: The y-axis scale is not specified in the given information, so we have used a general scale in the graph above.
First, Andrew travels a total of 4 miles in the first 15 minutes at a constant speed. So, we can plot a point at (15, 4) on the graph.
Then, Andrew rests for 10 minutes. We can represent this as a horizontal line segment on the graph from (15, 4) to (25, 4) to denote that he remains at the same distance from home during this period.
After resting, Andrew rides his bike home in the next 20 minutes. Since the total journey from home to a destination and back home takes 20 minutes, we can represent this as a diagonal line segment on the graph from (25, 4) to (45, 0) to show that he returns to his starting point.
The graph should show a diagonal line segment from (0,0) to (15,4), a horizontal line segment from (15,4) to (25,4), and another diagonal line segment from (25,4) to (45,0).
Here's a visual representation of the graph:
|
5 |
|
|
4 ---•--------•----------•--
0 15 25 45
minutes
Note: The y-axis scale is not specified in the given information, so we have used a general scale in the graph above.