What's the problem? A straightforward integration. The only wrinkle arises because the boundary changes at x=1. The area is
∫[0,1] e^x dx + ∫[1,4] e^x - ln(x) dx
Which integral gives the area of the region in the first quadrant bounded by the axes, y = e^x, x = e^y, and the line x = 4?
The answer is an integral.
I know y=e^x has no area bounded, but I don't know how to incorporate it all.
3 answers
OH I completely forgot to do the "+". I kept typing in the answer without the "+" and kept getting it wrong and decided to get help on the last try. Thank you very much Steve.
good. I guess we could also have written it as
∫[0,4] e^x - ∫[1,4] ln(x) dx
∫[0,4] e^x - ∫[1,4] ln(x) dx
2 answers