which inequality is true if x=3.04/1.48, y = 1.99+0.33, and

z = (1.3)^3?

answer is either:
y<z<x
y<x<z
x<z<y
x<y<z

1 answer

use your calculator to evaluate x, y and z

once you have all 3 as decimals, it should be easy to determine the correct answer.