Which has the greater acceleration, a car that increases its speed from 50 to 62 km/h, or a bike that goes from 0 to 12 km/h in the same time?

2 answers

a1 = (v-Vo)/t = (62-50)/t = 12/t.
a2 = (0-12) = -12/t.

Since their times and change in speed
are equal, the magnitude of their acceleration are equal. The neg. sign
means the bike was stopping or slowing
down.
The accelerations are the same.