To determine the correct formula that represents the points (1, 5), (2, 7), (3, 9), and (4, 11), we can start by looking for a linear relationship.
Let’s analyze the points:
- When \( x = 1 \), \( y = 5 \)
- When \( x = 2 \), \( y = 7 \)
- When \( x = 3 \), \( y = 9 \)
- When \( x = 4 \), \( y = 11 \)
We can observe that the values of \( y \) increase by 2 for every increase of 1 in \( x \):
\[ \begin{align*} 2 & \text{ (from } 5 \text{ to } 7) \ 2 & \text{ (from } 7 \text{ to } 9) \ 2 & \text{ (from } 9 \text{ to } 11) \ \end{align*} \]
This suggests a linear relationship of the form \( y = mx + b \).
To find the slope \( m \):
\[ m = \frac{\Delta y}{\Delta x} = \frac{2}{1} = 2 \]
Now, we can use one point to find the y-intercept \( b \). Using point (1, 5):
\[ 5 = 2(1) + b \] \[ 5 = 2 + b \] \[ b = 5 - 2 = 3 \]
Thus, the linear equation that describes the points is:
\[ y = 2x + 3 \]
Now, to visualize the graph, we can plot the line \( y = 2x + 3 \) and see if it passes through the given points:
- For \( x = 1 \): \( y = 2(1) + 3 = 5 \)
- For \( x = 2 \): \( y = 2(2) + 3 = 7 \)
- For \( x = 3 \): \( y = 2(3) + 3 = 9 \)
- For \( x = 4 \): \( y = 2(4) + 3 = 11 \)
Since all points match and are on the line, the graph of the line \( y = 2x + 3 \) accurately represents the data points (1, 5), (2, 7), (3, 9), and (4, 11).
If you can provide the graphs or options to choose from, I can help identify which one accurately represents this equation.