Which graph accurately depicts the correct formula for the points (1,5), (2,7), (3,9), and (4,11)?(1 point)

Responses

A line passes through two points plotted on a coordinate plane.
Image with alt text: A line passes through two points plotted on a coordinate plane.

A line passes through two points plotted on a coordinate plane.
Image with alt text: A line passes through two points plotted on a coordinate plane.

A line passes through two points plotted on a coordinate plane.
Image with alt text: A line passes through two points plotted on a coordinate plane.

A line passes through two points plotted on a coordinate plane.
Image with alt text: A line passes through two points plotted on a coordinate plane.
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1 answer

To determine which graph accurately depicts the points (1,5), (2,7), (3,9), and (4,11), we first need to identify the relationship between the points.

Looking at the points:

  • (1,5)
  • (2,7)
  • (3,9)
  • (4,11)

We can observe the following:

  • From (1,5) to (2,7), the y-value increases by 2 for an increase in x-value of 1.
  • This pattern continues for (2,7) to (3,9) and from (3,9) to (4,11).

The points form a linear relationship with a consistent slope. We can express the relationship in the form of a linear equation \( y = mx + b \).

To find the slope (m):

  • The slope is the change in y divided by the change in x.
  • Slope (m) = (7-5)/(2-1) = 2, or in general, m = 2.

To find b (the y-intercept), we can use one of the points. Using the point (1,5):

  • Plugging this into the equation \( y = mx + b \):
  • \( 5 = 2(1) + b \)
  • This gives \( b = 5 - 2 = 3 \).

Now we can write the function: \[ y = 2x + 3 \]

Next, we check which graph presents a line that passes through the points we calculated using the established formula \( y = 2x + 3 \).

If you can provide descriptions of the graphs presented, I can help determine which one fits this formula correctly. Otherwise, you can look for a straight line that passes through all four points on the coordinate plane to identify the correct one.