Asked by x
Which function is nonlinear?(1 point)
Responses
y=5/8x
y is equal to 5 eighths x
y=8⋅2x−9
y is equal to 8 times 2 x minus 9
y=12x+8
y is equal to 12 x plus 8
y=5.2 (7.1)x
Responses
y=5/8x
y is equal to 5 eighths x
y=8⋅2x−9
y is equal to 8 times 2 x minus 9
y=12x+8
y is equal to 12 x plus 8
y=5.2 (7.1)x
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which function is nonlinear, let's analyze each of the given functions:
1. **y = (5/8)x**: This is a linear function because it is in the form \(y = mx + b\), where \(m = 5/8\) and \(b = 0\).
2. **y = 8·2^(x − 9)**: This is an exponential function because it includes the variable \(x\) as an exponent. Thus, this function is nonlinear.
3. **y = 12x + 8**: This is also a linear function in the form \(y = mx + b\), where \(m = 12\) and \(b = 8\).
4. **y = 5.2(7.1)^x**: This is another exponential function (similar to the second function) because of the variable \(x\) being in the exponent.
From these analyses, the two nonlinear functions are **y = 8·2^(x − 9)** and **y = 5.2(7.1)^x**. However, since you are looking for a single nonlinear function, the first one listed as nonlinear is:
**y = 8·2^(x − 9)**.
This is the function you would choose as nonlinear.
1. **y = (5/8)x**: This is a linear function because it is in the form \(y = mx + b\), where \(m = 5/8\) and \(b = 0\).
2. **y = 8·2^(x − 9)**: This is an exponential function because it includes the variable \(x\) as an exponent. Thus, this function is nonlinear.
3. **y = 12x + 8**: This is also a linear function in the form \(y = mx + b\), where \(m = 12\) and \(b = 8\).
4. **y = 5.2(7.1)^x**: This is another exponential function (similar to the second function) because of the variable \(x\) being in the exponent.
From these analyses, the two nonlinear functions are **y = 8·2^(x − 9)** and **y = 5.2(7.1)^x**. However, since you are looking for a single nonlinear function, the first one listed as nonlinear is:
**y = 8·2^(x − 9)**.
This is the function you would choose as nonlinear.
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