To determine which object has the least kinetic energy when it collides on the ground, we need to calculate the kinetic energy for each object.
The formula for calculating kinetic energy is K.E. = 0.5 * mass * velocity^2.
Let's calculate the kinetic energy for each option:
A) 120 KG of water falling at 12 m/s
K.E. = 0.5 * 120 * (12)^2 = 86,400 Joules
B) 120 KG of sand falling at 12 m/s
K.E. = 0.5 * 120 * (12)^2 = 86,400 Joules
C) 12 KG of water falling at 10 m/s
K.E. = 0.5 * 12 * (10)^2 = 600 Joules
D) 12 KG of sand falling at 8 m/s
K.E. = 0.5 * 12 * (8)^2 = 384 Joules
Comparing the calculated kinetic energy values, we can see that option D) 12 KG of sand falling at 8 m/s has the least kinetic energy among the given options.
Which following object has the LEAST kinetic energy when it collides on the ground?
A) 120 KG of water falling at 12 m/s
B) 120 KG of sand falling at 12 m/s
C) 12 KG of water falling at 10 m/s
D) 12 KG of sand falling at 8 m/s
1 answer
1 answer