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Which falling object will result in the least kinetic energy when it collides with the ground?(1 point) Responses 10 grams of d...Asked by Augustin Garcia
Which falling object will result in the least kinetic energy when it collides with the ground?(1 point)
Responses
10 grams of dirt falling at 2 m/s
10 grams of dirt falling at 2 m/s
100 grams of water falling at 10 m/s
100 grams of water falling at 10 m/s
10 grams of water falling at 1 m/s
10 grams of water falling at 1 m/s
100 grams of dirt falling at 15 m/s
100 grams of dirt falling at 15 m/s
Responses
10 grams of dirt falling at 2 m/s
10 grams of dirt falling at 2 m/s
100 grams of water falling at 10 m/s
100 grams of water falling at 10 m/s
10 grams of water falling at 1 m/s
10 grams of water falling at 1 m/s
100 grams of dirt falling at 15 m/s
100 grams of dirt falling at 15 m/s
Answers
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Answered by
GPT-4o mini
To determine which falling object will result in the least kinetic energy upon collision with the ground, we can use the formula for kinetic energy (KE):
\[
KE = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the object in kilograms, and \( v \) is the velocity in meters per second.
Let's calculate the kinetic energy for each option:
1. **10 grams of dirt falling at 2 m/s:**
- Mass: \( m = 10 \, \text{grams} = 0.01 \, \text{kg} \)
- Velocity: \( v = 2 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.01 \times (2)^2 = \frac{1}{2} \times 0.01 \times 4 = 0.02 \, \text{J} \)
2. **100 grams of water falling at 10 m/s:**
- Mass: \( m = 100 \, \text{grams} = 0.1 \, \text{kg} \)
- Velocity: \( v = 10 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.1 \times (10)^2 = \frac{1}{2} \times 0.1 \times 100 = 5.0 \, \text{J} \)
3. **10 grams of water falling at 1 m/s:**
- Mass: \( m = 10 \, \text{grams} = 0.01 \, \text{kg} \)
- Velocity: \( v = 1 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.01 \times (1)^2 = \frac{1}{2} \times 0.01 \times 1 = 0.005 \, \text{J} \)
4. **100 grams of dirt falling at 15 m/s:**
- Mass: \( m = 100 \, \text{grams} = 0.1 \, \text{kg} \)
- Velocity: \( v = 15 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.1 \times (15)^2 = \frac{1}{2} \times 0.1 \times 225 = 11.25 \, \text{J} \)
Now, summarizing the kinetic energies:
- 10 grams of dirt at 2 m/s: **0.02 J**
- 100 grams of water at 10 m/s: **5.0 J**
- 10 grams of water at 1 m/s: **0.005 J**
- 100 grams of dirt at 15 m/s: **11.25 J**
Based on the calculations, the object that results in the least kinetic energy upon collision with the ground is **10 grams of water falling at 1 m/s (0.005 J)**.
\[
KE = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the object in kilograms, and \( v \) is the velocity in meters per second.
Let's calculate the kinetic energy for each option:
1. **10 grams of dirt falling at 2 m/s:**
- Mass: \( m = 10 \, \text{grams} = 0.01 \, \text{kg} \)
- Velocity: \( v = 2 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.01 \times (2)^2 = \frac{1}{2} \times 0.01 \times 4 = 0.02 \, \text{J} \)
2. **100 grams of water falling at 10 m/s:**
- Mass: \( m = 100 \, \text{grams} = 0.1 \, \text{kg} \)
- Velocity: \( v = 10 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.1 \times (10)^2 = \frac{1}{2} \times 0.1 \times 100 = 5.0 \, \text{J} \)
3. **10 grams of water falling at 1 m/s:**
- Mass: \( m = 10 \, \text{grams} = 0.01 \, \text{kg} \)
- Velocity: \( v = 1 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.01 \times (1)^2 = \frac{1}{2} \times 0.01 \times 1 = 0.005 \, \text{J} \)
4. **100 grams of dirt falling at 15 m/s:**
- Mass: \( m = 100 \, \text{grams} = 0.1 \, \text{kg} \)
- Velocity: \( v = 15 \, \text{m/s} \)
- \( KE = \frac{1}{2} \times 0.1 \times (15)^2 = \frac{1}{2} \times 0.1 \times 225 = 11.25 \, \text{J} \)
Now, summarizing the kinetic energies:
- 10 grams of dirt at 2 m/s: **0.02 J**
- 100 grams of water at 10 m/s: **5.0 J**
- 10 grams of water at 1 m/s: **0.005 J**
- 100 grams of dirt at 15 m/s: **11.25 J**
Based on the calculations, the object that results in the least kinetic energy upon collision with the ground is **10 grams of water falling at 1 m/s (0.005 J)**.
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