Let's address each part of your question step by step.
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Which factors of the base would help simplify the expression \( 16^{1/4} \)?
- The best factorization for simplification is:
- 16 = 4 ⋅ 4
- This allows us to express \( 16^{1/4} = (4^2)^{1/4} = 4^{2 \cdot (1/4)} = 4^{1/2} = \sqrt{4} = 2 \).
- Alternatively, we could also express 16 as:
- 16 = 2 ⋅ 2 ⋅ 2 ⋅ 2 (which indicates that \( 16 = 2^4 \)).
- But for clarity, the most straightforward simplification comes from using \( 16 = 4 \cdot 4 \).
- The best factorization for simplification is:
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Given that the cube root of 27 is 3, what is \( 27^{4/3} \)?
- Since \( 27^{1/3} = 3 \), we can rewrite \( 27^{4/3} \) as:
- \( (27^{1/3})^4 = 3^4 = 81 \).
- So the answer is 81.
- Since \( 27^{1/3} = 3 \), we can rewrite \( 27^{4/3} \) as:
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What is the correct simplification of \( 25^{3/2} \)?
- We can express \( 25^{3/2} \) as:
- \( (25^{1/2})^3 = (5)^3 = 125 \).
- Thus, the answer is 125.
- We can express \( 25^{3/2} \) as:
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Given that the meaning of a rational exponent can be connected to the meaning of a root, how can you rewrite \( 5^{-\sqrt{3}} \) using a rational exponent?
- The notation \( 5^{-\sqrt{3}} \) is already in the form of rational exponent but if you want it in the form of \( 5^{-3^{1/2}} \), that works also.
- The correct response would be:
- \( 5^{-\frac{1}{3}} \) (which is not explicitly listed here).
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How can you rewrite \( 8^{1/2} \) using a root?
- The expression \( 8^{1/2} \) represents the square root of 8, which can be simplified to:
- \( \sqrt{8} \) or written out as \( 8^{1/2} = \sqrt{8} \).
- The best option that closely aligns is:
- \( \sqrt{8} \) which can be termed as \( 8^{1/2} \).
- The expression \( 8^{1/2} \) represents the square root of 8, which can be simplified to:
If you look for specific answers based on your listed responses for the last few parts, here's a summary of the answers:
- Factors that help simplify \( 16^{1/4} \): \(16 = 4 \cdot 4\)
- \( 27^{4/3} = 81 \)
- \( 25^{3/2} = 125 \)
- \( 5^{-\sqrt{3}} = 5^{-3^{1/2}} \)
- Rewrite \( 8^{1/2} = \sqrt{8} \) or \( \sqrt{8} \) is a direct connection.