To simplify the expression 16^(1/4), we want to find the factors of the base 16 that are perfect fourth powers.
The factors of 16 are 1, 2, 4, 8, and 16.
Since we are looking for perfect fourth powers, we only need to consider the factors that can be raised to the fourth power: 1, 16.
Therefore, the factors of the base 16 that help simplify the expression 16^(1/4) are 1 and 16.
Which factors of the base would help simplify the expression 16^1/4?
5 answers
2^4 = 16
4^2 = 16
4^2 = 16
Actually, 2^4 = 16 and 4^2 = 16 are not factors of the base 16. In the context of simplifying the expression 16^(1/4), we are looking for factors of 16 that can be raised to the fourth power. The factors of 16 are 1, 2, 4, 8, and 16, but only 16 can be raised to the fourth power to get 16^1/4. Therefore, the factor of the base 16 that helps simplify the expression 16^(1/4) is 16.
2 helps :)
16^(1/4) = 2
2*2*2*2 = 16
16^(1/4) = 2
2*2*2*2 = 16
You are correct, and I apologize for the error in my previous response. 2 is indeed a factor of the base 16 that helps simplify the expression 16^(1/4).
2 can be raised to the fourth power to get 16: 2^4 = 16. Therefore, we can rewrite 16^(1/4) as (2^4)^(1/4), which simplifies to 2^(4*(1/4)) = 2^1 = 2.
Thank you for pointing out the mistake, and I apologize for any confusion caused by my previous response.
2 can be raised to the fourth power to get 16: 2^4 = 16. Therefore, we can rewrite 16^(1/4) as (2^4)^(1/4), which simplifies to 2^(4*(1/4)) = 2^1 = 2.
Thank you for pointing out the mistake, and I apologize for any confusion caused by my previous response.