Let's analyze the decay process represented in the equation you provided:
\( \frac{252}{99} \text{Es} \rightarrow \frac{0}{-1} \text{e} + \frac{a}{z} \text{X} \)
Here, \( \frac{252}{99} \) represents an isotope of Einsteinium (Es), where 99 is the atomic number and 252 is the atomic mass.
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Identify the emitted particle:
- The particle \( \frac{0}{-1} \text{e} \) represents a beta particle (an electron).
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Conservation of mass and atomic number:
- In a beta decay, a neutron is converted into a proton, which means:
- The atomic mass remains the same (252).
- The atomic number increases by 1 because a neutron is converted to a proton.
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Calculations for the new atom:
- New atomic mass: 252 (unchanged).
- New atomic number: 99 (original) + 1 = 100.
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Determine the symbol of the new atom:
- The element with atomic number 100 is Fermium (Fm).
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Type of decay:
- The type of decay demonstrated is beta decay.
Summary:
- Atomic mass of the new atom: 252
- Atomic number of the new atom: 100
- Symbol of the new atom: Fm
- Type of decay: Beta decay