To find the sum of the expressions \(3(4x-5)\) and \(4(x+2)\), we start by distributing in each expression.
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Distributing \(3\) in \(3(4x-5)\): \[ 3(4x) - 3(5) = 12x - 15 \]
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Distributing \(4\) in \(4(x+2)\): \[ 4(x) + 4(2) = 4x + 8 \]
Now we add the two results together: \[ (12x - 15) + (4x + 8) \]
Combining like terms:
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For \(x\) terms: \[ 12x + 4x = 16x \]
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For constant terms: \[ -15 + 8 = -7 \]
Putting it all together, we have: \[ 16x - 7 \]
Thus, the answer is: \[ \text{B. } 16x - 7 \]