To find an expression equivalent to \(\left(\frac{1}{2}a + 5\right)\left(\frac{3}{2}a + 1\right)\), we will use the distributive property (also known as the FOIL method for binomials).
Here are the steps:
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Multiply the first terms: \[ \frac{1}{2}a \cdot \frac{3}{2}a = \frac{3}{4}a^2 \]
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Multiply the outer terms: \[ \frac{1}{2}a \cdot 1 = \frac{1}{2}a \]
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Multiply the inner terms: \[ 5 \cdot \frac{3}{2}a = \frac{15}{2}a \]
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Multiply the last terms: \[ 5 \cdot 1 = 5 \]
Now, we combine all these results: \[ \frac{3}{4}a^2 + \frac{1}{2}a + \frac{15}{2}a + 5 \]
Next, we combine the like terms (\(\frac{1}{2}a\) and \(\frac{15}{2}a\)): \[ \frac{1}{2}a + \frac{15}{2}a = \frac{16}{2}a = 8a \]
Now we can write the expression as: \[ \frac{3}{4}a^2 + 8a + 5 \]
Thus, the expression equivalent to \(\left(\frac{1}{2}a + 5\right)\left(\frac{3}{2}a + 1\right)\) is: \[ \frac{3}{4}a^2 + 8a + 5 \]