Which expression is equivalent to

Question

`\frac{40x^{-3}y^{5}}{8x^{-2}y^{-2}}`

for all values for `x` and `y` where the expression is defined?

Answer 1

To simplify the expression, we can divide the numerator by the denominator:

`\frac{40x^{-3}y^{5}}{8x^{-2}y^{-2}} = \frac{40}{8} \cdot \frac{x^{-3}}{x^{-2}} \cdot \frac{y^{5}}{y^{-2}}`

Simplifying further, we can divide 40 by 8 to get 5:

`\frac{40}{8} \cdot \frac{x^{-3}}{x^{-2}} \cdot \frac{y^{5}}{y^{-2}} = 5 \cdot x^{-3-(-2)} \cdot y^{5-(-2)}`

Simplifying the exponents will yield:

`5 \cdot x^{-1} \cdot y^{7}`

Multiplying 5 with x^-1 and y^7 gives the simplified expression:

`5x^{-1}y^{7}`

Therefore, the expression `\frac{40x^{-3}y^{5}}{8x^{-2}y^{-2}}` is equivalent to `5x^{-1}y^{7}`.

Answer 2

Soo 5xy^7?

Answer 3

5xy^7?