To simplify the expression \((z+4)(z-4)\), we can use the difference of squares formula, which states that:
\[ (a+b)(a-b) = a^2 - b^2 \]
In this case, we have \(a = z\) and \(b = 4\). Applying the formula:
\[ (z+4)(z-4) = z^2 - 4^2 = z^2 - 16 \]
Now, let's compare this result with the provided options:
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z² + 4z - 4z - 16: This simplifies to \(z^2 - 16\) (the \(4z\) and \(-4z\) cancel out).
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2z² - z² - 8: This simplifies to \(z^2 - 8\), which is not equivalent.
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z² - 8z - 16: This is \(z^2 - 8z - 16\), which is not equivalent.
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z(z) + 4z(z) - 4(4): This simplifies to \(z^2 + 4z^2 - 16\), which is not equivalent.
The correct answer is the first option: z² + 4z - 4z - 16.