To factor the trinomial \(9x^2 - 9x - 4\), we can look for two numbers that multiply to \(a \cdot c = 9 \cdot (-4) = -36\) and add to \(b = -9\).
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Identify \(a\), \(b\), and \(c\):
- \(a = 9\)
- \(b = -9\)
- \(c = -4\)
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Factors of \(-36\):
- The pairs of factors that multiply to \(-36\) include:
- (1, -36)
- (2, -18)
- (3, -12)
- (4, -9)
- (6, -6)
- (-1, 36)
- (-2, 18)
- (-3, 12)
- (-4, 9)
- (-6, 6)
- The pairs of factors that multiply to \(-36\) include:
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Finding the correct pair:
- Among these pairs, the pair that adds to \(-9\) is \(3\) and \(-12\):
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Rewrite the trinomial: \[ 9x^2 + 3x - 12x - 4 \]
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Group the terms: \[ (9x^2 + 3x) + (-12x - 4) \]
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Factor each group: \[ 3x(3x + 1) - 4(3x + 1) \]
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Factor out the common binomial: \[ (3x + 1)(3x - 4) \]
Thus, the expression \(9x^2 - 9x - 4\) is equivalent to \((3x + 1)(3x - 4)\).
So the final answer is: \[ \boxed{(3x + 1)(3x - 4)} \]