To simplify the expression \( \frac{4^{-8}}{4^{-7}} \times 4^0 \), we can follow the rules of exponents.
-
Dividing powers with the same base: \[ \frac{a^m}{a^n} = a^{m-n} \] In our case: \[ \frac{4^{-8}}{4^{-7}} = 4^{-8 - (-7)} = 4^{-8 + 7} = 4^{-1} \]
-
Calculating \( 4^0 \): \[ 4^0 = 1 \]
-
Combining the results: Now we have: \[ 4^{-1} \times 4^0 = 4^{-1} \times 1 = 4^{-1} \]
So, the expression simplifies to \( 4^{-1} \).
The equivalent expression from the options provided is: \[ -1 \]
Thus, the answer is \(-1\).