To simplify the expression \(\frac{4^{-5}}{4^{7}} \cdot 4^{-7}\), we can use the properties of exponents.
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Start with the given expression: \[ \frac{4^{-5}}{4^{7}} \cdot 4^{-7} \]
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Simplify the fraction \(\frac{4^{-5}}{4^{7}}\) using the quotient rule for exponents: \[ \frac{a^m}{a^n} = a^{m-n} \] Here, \(a = 4\), \(m = -5\), and \(n = 7\): \[ \frac{4^{-5}}{4^{7}} = 4^{-5 - 7} = 4^{-12} \]
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Now, multiply by \(4^{-7}\): \[ 4^{-12} \cdot 4^{-7} \] Again using the product rule for exponents: \[ a^m \cdot a^n = a^{m+n} \] Here, \(m = -12\) and \(n = -7\): \[ 4^{-12} \cdot 4^{-7} = 4^{-12 - 7} = 4^{-19} \]
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The final expression is \(4^{-19}\). This can also be expressed as: \[ \frac{1}{4^{19}} \]
Now, let's match this with the options provided:
- \(\frac{1}{4^{21}}\)
- \(\frac{1}{4^{19}}\) (which is our result)
- \(\frac{1}{4^{20}}\)
Thus, the correct answer is: \[ \frac{1}{4^{19}} \]