To find which expression for \( A \) makes the equation \( A = 5 - \frac{1}{13} \) true, we already calculated that:
\[ A = 5 - \frac{1}{13} = \frac{64}{13} \]
Now we need to evaluate the provided options to see which one is equal to \( \frac{64}{13} \).
- Option 1: \( A = \frac{123 + 13}{\text{not valid as it is not simplified or clear}} \)
- Option 2: \( A = \frac{123 - 13}{\text{not valid as it is not simplified or clear}} \)
- Option 3: \( A = -\frac{123 + 13}{\text{not valid as it is not simplified or clear}} \)
- Option 4: \( A = \frac{153 + 13}{\text{not valid as it is not simplified or clear}} \)
Since the original options were not presented clearly, we cannot directly assess them. However, let's assume some plausible interpretations based on your hints and simplify:
- Option 1: Let's assume it is intended as \( \frac{123 + 13}{x} = \frac{136}{x} \)
- Option 2: Let's assume it is intended as \( \frac{123 - 13}{x} = \frac{110}{x} \)
- Option 3: Let's assume it is intended as \( -\frac{123 + 13}{x} = -\frac{136}{x} \)
- Option 4: Let's assume it is intended as \( \frac{153 + 13}{x} = \frac{166}{x} \)
To check if any of these equal \( \frac{64}{13} \), we can set \( \frac{a}{x} = \frac{64}{13} \) and solve for \( a \):
This means we need to find \( a \) such that: \[ a = \frac{64 \cdot x}{13} \]
For each option given the context of \( A \):
-
\(\frac{123 + 13}{x} \) doesn't seem to simplify to \( \frac{64}{13} \)
-
\(\frac{123 - 13}{x} \) gives us \( \frac{110}{x} \)
So the most appropriate expression for it to equal \( \frac{64}{13} \) isn’t clear cut without proper labeling.
However, since we determined that \( \frac{64}{13} \) is indeed the value of \( A \), the specific expression reflecting that value must directly calculate \( \frac{64}{13} \) or simplify to it upon evaluation.
If you can clarify or provide more specific expressions for options, I would be able to evaluate them accurately. Otherwise, based on what we calculated earlier, it seems you were on the right track concluding that \( A \) should equal \( \frac{64}{13} \).