Which expression correctly shows p(x)=9x5−9x2 factored completely over the integers?

Question

9x2(x2+1)(x2−1)
(x−1)(x2+x+1)
9x2(x−1)(x2+x+1)
9x2(x2−2x+1)

is it (x−1)(x2+x+1)

Answer 1

Did you check your answer? It's not even a 5th degree polynomial.
You should have stopped here:
9x^2(x−1)(x^2+x+1)
The next line is bogus, since x^2-2x+1 = (x-1)^2
And you can't just discard factors as you go.

Answer 2

Oh okay I understand what you are saying thank you. I am really struggling in this subject no matter what videos I watch and go over my notes I just cant get it

Answer 3

Multiply. (3x + 5)(3x – 5)
A. 9x2 – 30x – 25
B. 9x2 + 30x + 25
C. 9x2 – 25
D. 9x2 + 25

Answer 4

The given expression is a difference of squares and can be written as:

(3x + 5)(3x - 5) = (3x)^2 - 5^2

= 9x^2 - 25

Therefore, the answer is (C) 9x2 – 25.