Which example correctly demonstrates polynomial subtraction?(1 point)

Question

Responses

(2x2+6x+1)−(3x2+3x+9)=−x2+3x−8
left parenthesis 2 x squared plus 6 x plus 1 right parenthesis minus left parenthesis 3 x squared plus 3 x plus 9 right parenthesis equals negative x squared plus 3 x minus 8

(2x2+6x+1)−(3x2+3x+9)=−5x2+3x−8
left parenthesis 2 x squared plus 6 x plus 1 right parenthesis minus left parenthesis 3 x squared plus 3 x plus 9 right parenthesis equals 2 x squared plus 6 x plus 1 minus 3 x squared minus 3 x minus 9

(2x2+6x+1)−(3x2+3x+9)=5x2+9x+10
left parenthesis 2 x squared plus 6 x plus 1 right parenthesis minus left parenthesis 3 x squared plus 3 x plus 9 right parenthesis equals 5 x squared plus 9 x plus 10

(2x2+6x+1)−(3x2+3x+9)=x2+3x+8

Answer 1

To determine the correct polynomial subtraction, we can perform the operation step-by-step for the expression:

\[ (2x^2 + 6x + 1) - (3x^2 + 3x + 9) \]

We can rewrite it as:

\[ 2x^2 + 6x + 1 - 3x^2 - 3x - 9 \]

Now, we will combine like terms:

1. For \(x^2\) terms: \[ 2x^2 - 3x^2 = -1x^2 = -x^2 \]

2. For \(x\) terms: \[ 6x - 3x = 3x \]

3. For constant terms: \[ 1 - 9 = -8 \]

Putting it all together, we get:

\[ -x^2 + 3x - 8 \]

Now, we will compare this result with the options provided:

1. \((2x^2 + 6x + 1)−(3x^2 + 3x + 9) = -x^2 + 3x - 8\) (Correct)
2. \((2x^2 + 6x + 1)−(3x^2 + 3x + 9) = -5x^2 + 3x - 8\) (Incorrect)
3. \((2x^2 + 6x + 1)−(3x^2 + 3x + 9) = 5x^2 + 9x + 10\) (Incorrect)
4. \((2x^2 + 6x + 1)−(3x^2 + 3x + 9) = x^2 + 3x + 8\) (Incorrect)

Therefore, the correct example that demonstrates polynomial subtraction is:

\((2x^2 + 6x + 1)−(3x^2 + 3x + 9) = -x^2 + 3x - 8\).