To determine which equations are already in the \(y = mx + b\) form, we need to convert all the given equations to this format.
Here’s the given list along with the transformations for each equation:
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Equation: \(y = 57 - 4\)
- Simplified: \(y = 53\)
- Form: \(y = 0x + 53\) (This is in \(y = mx + b\) form)
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Equation: \(y = -2x + 3\)
- Form: This is already in \(y = mx + b\) form.
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Equation: \(y = 3x + 1\)
- Form: This is already in \(y = mx + b\) form.
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Equation: \(2y = 6x + 2\)
- Rearranging: Divide everything by 2:
- Result: \(y = 3x + 1\)
- Form: This is in \(y = mx + b\) form.
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Equation: \(y - 5x = 2\)
- Rearranging: Add \(5x\) to both sides:
- Result: \(y = 5x + 2\)
- Form: This is in \(y = mx + b\) form.
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Equation: \(y - 4g + 1 = 0\)
- Rearranging: Add \(4g - 1\) to both sides:
- Result: \(y = 4g - 1\)
- Form: This is not strictly in \(y = mx + b\) form as there is a "g" variable.
Summary of Results:
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Equations already in \(y = mx + b\) form:
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- \(y = -2x + 3\)
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- \(y = 3x + 1\)
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- \(y = 3x + 1\) (from the original)
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- \(y = 5x + 2\)
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- \(y = 53\) (in the general linear form, where \(m = 0\))
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Not in the correct form:
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- \(y = 4g - 1\)
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Finalized Equations:
- \(y = 53\) (or \(y = 0x + 53\))
- \(y = -2x + 3\)
- \(y = 3x + 1\)
- \(y = 3x + 1\) (simplified)
- \(y = 5x + 2\)
- \(y = 4g - 1\) (not \(y = mx + b\))
Thus, the equations in \(y = mx + b\) form are 1, 2, 3, 4, and 5 (with 6 being excluded due to having a different variable).