Asked by DL
Which equations are already in y=mx+b form?
1. y=5x-4
2. y=-2×+3
3. y=3×+1
4. 2y=6×+2
5. y-5×=2
6. y-4×+1=0
1. y=5x-4
2. y=-2×+3
3. y=3×+1
4. 2y=6×+2
5. y-5×=2
6. y-4×+1=0
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which equations are in the \( y = mx + b \) form, we need to identify equations where \( y \) is isolated on one side of the equation. This means rearranging the equations if necessary.
Let's analyze each equation:
1. \( y = 5x - 4 \)
- This is already in \( y = mx + b \) form.
2. \( y = -2x + 3 \)
- This is already in \( y = mx + b \) form.
3. \( y = 3x + 1 \)
- This is already in \( y = mx + b \) form.
4. \( 2y = 6x + 2 \)
- Divide both sides by 2:
\[ y = 3x + 1 \]
- This is now in \( y = mx + b \) form.
5. \( y - 5x = 2 \)
- Rearranging gives:
\[ y = 5x + 2 \]
- This is now in \( y = mx + b \) form.
6. \( y - 4x + 1 = 0 \)
- Rearranging gives:
\[ y = 4x - 1 \]
- This is now in \( y = mx + b \) form.
In summary, all of the equations can be expressed in \( y = mx + b \) form:
1. Yes
2. Yes
3. Yes
4. Yes
5. Yes
6. Yes
Let's analyze each equation:
1. \( y = 5x - 4 \)
- This is already in \( y = mx + b \) form.
2. \( y = -2x + 3 \)
- This is already in \( y = mx + b \) form.
3. \( y = 3x + 1 \)
- This is already in \( y = mx + b \) form.
4. \( 2y = 6x + 2 \)
- Divide both sides by 2:
\[ y = 3x + 1 \]
- This is now in \( y = mx + b \) form.
5. \( y - 5x = 2 \)
- Rearranging gives:
\[ y = 5x + 2 \]
- This is now in \( y = mx + b \) form.
6. \( y - 4x + 1 = 0 \)
- Rearranging gives:
\[ y = 4x - 1 \]
- This is now in \( y = mx + b \) form.
In summary, all of the equations can be expressed in \( y = mx + b \) form:
1. Yes
2. Yes
3. Yes
4. Yes
5. Yes
6. Yes
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