To find a line that is perpendicular to a given line, we need to find the negative reciprocal of the coefficient of x.
The given line is 6x + 7y = -49.
The coefficient of x is 6.
The negative reciprocal of 6 is -1/6.
Therefore, the line that is perpendicular to the given line has the equation y = (-1/6)x + b, where b is the y-intercept.
None of the provided answer choices have the correct equation.
Which equation represents a line which is perpendicular to the line 6, x, plus, 7, y, equals, minus, 496x+7y=−49?
Answer
Multiple Choice Answers
y, equals, minus, start fraction, 7, divided by, 6, end fraction, x, minus, 8y=−
6
7
x−8
y, equals, minus, start fraction, 6, divided by, 7, end fraction, x, plus, 7y=−
7
6
x+7
y, equals, start fraction, 7, divided by, 6, end fraction, x, minus, 5y=
6
7
x−5
y, equals, start fraction, 6, divided by, 7, end fraction, x, minus, 3y=
7
6
x−3
1 answer
1 answer