To find which equation matches the solution set of {5}, we can solve each of the provided equations for \( x \) and check which one gives the solution \( x = 5 \).
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Equation: \( \frac{3x}{5} + 4 = 7 \) \[ \frac{3x}{5} = 7 - 4 \ \frac{3x}{5} = 3 \ 3x = 15 \ x = 5 \]
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Equation: \( x^2 - 10 = 15 \) \[ x^2 = 15 + 10 \ x^2 = 25 \ x = 5 \quad \text{or} \quad x = -5 \]
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Equation: \( x + x - 9 = 1 + x \) \[ 2x - 9 = 1 + x \ 2x - x = 1 + 9 \ x = 10 \quad (\text{not } 5) \]
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Equation: \( 2x - 20 = 30 \) \[ 2x = 30 + 20 \ 2x = 50 \ x = 25 \quad (\text{not } 5) \]
From the above calculations, we see that the first equation \( \frac{3x}{5} + 4 = 7 \) and the second equation \( x^2 - 10 = 15 \) both yield \( x = 5 \). However, since we are looking for one equation that matches the solution set of {5} exactly, we should select:
Answer: \( \frac{3x}{5} + 4 = 7 \)