To determine which equation matches the solution set of {5}, we can solve each equation and check if \( x = 5 \) is a solution.
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Equation: \( 2x - 20 = 30 \)
\[ 2x - 20 = 30 \ 2x = 30 + 20 \ 2x = 50 \ x = \frac{50}{2} \ x = 25 \]
Solution: \( x = 25 \) (not \( 5 \))
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Equation: \( x + x - 9 = 1 + x \)
\[ 2x - 9 = 1 + x \ 2x - x = 1 + 9 \ x = 10 \]
Solution: \( x = 10 \) (not \( 5 \))
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Equation: \( x^2 - 10 = 15 \)
\[ x^2 - 10 = 15 \ x^2 = 15 + 10 \ x^2 = 25 \ x = 5 \quad \text{or} \quad x = -5 \]
Solution: \( x = 5 \) (this works!)
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Equation: \( \frac{3x}{5} + 4 = 7 \)
\[ \frac{3x}{5} = 7 - 4 \ \frac{3x}{5} = 3 \ 3x = 3 \times 5 \ 3x = 15 \ x = \frac{15}{3} \ x = 5 \]
Solution: \( x = 5 \) (this also works!)
Conclusion: Both equations \( x^2 - 10 = 15 \) and \( \frac{3x}{5} + 4 = 7 \) yield the solution \( x = 5 \). Thus, the equations that match the solution set of {5} are:
- \( x^2 - 10 = 15 \)
- \( \frac{3x}{5} + 4 = 7 \)