Let's analyze each question one by one.
Question 1:
Which equation matches the solution set of {5}?
We can solve each equation to see which one has 5 as the only solution.
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\(x + x - 9 = 1 + x\): \[ 2x - 9 = 1 + x \] \[ 2x - x = 1 + 9 \] \[ x = 10 \] (not a match)
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\(2x - 20 = 30\): \[ 2x = 50 \] \[ x = 25 \] (not a match)
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\(x^2 - 10 = 15\): \[ x^2 = 25 \] \[ x = 5 \quad \text{or} \quad x = -5 \] (not a match, as it also includes -5)
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\(3x + 4 = 7\): \[ 3x = 3 \] \[ x = 1 \] (not a match)
None of the equations have {5} as the only solution.
Question 2:
What is the value of p in the following equation?
\(20p - 3 = 5\): Add 3 to both sides: \[ 20p = 8 \] Divide by 20: \[ p = \frac{8}{20} = \frac{2}{5} \] None of the provided answers (1, 3, 5, 7) match \( \frac{2}{5} \).
Question 3:
Which of the following equations has the solution set \(x = {-95, 3}\)?
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\((x - 3)(9x + 5) = 0\): Solutions are \(x = 3\) and \(x = -\frac{5}{9}\) (not a match)
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\(-3x(5x + 9) = 0\): Solutions are \(x = 0\) or \(x = -\frac{9}{5}\) (not a match)
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\((x + 3)(9x - 5) = 0\): Solutions are \(x = -3\) and \(x = \frac{5}{9}\) (not a match)
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\((x - 3)(5x + 9) = 0\): Solutions are \(x = 3\) and \(x = -\frac{9}{5}\) (not a match)
Based on the equations and their solutions, we have the results as:
- No equation in question 1 matched {5}.
- The solution to question 2 was not in the provided answers.
- Question 3 did not match the solution set of \([-95, 3]\) in any of the options.
Let me know if you would like to go over specific equations again or need further assistance!
2 answers