To determine which equation has the solution \( x = 5 \), we can substitute \( x = 5 \) into each option and check if the equations hold true.
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Option 1: \( 4x + 9 = 29 \) \[ 4(5) + 9 = 20 + 9 = 29 \quad \text{(True)} \]
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Option 2: \( 8x - 4 = 48 \) \[ 8(5) - 4 = 40 - 4 = 36 \quad \text{(False)} \]
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Option 3: \( 5x + 7 = 82 \) \[ 5(5) + 7 = 25 + 7 = 32 \quad \text{(False)} \]
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Option 4: \( 4x + 6 = -26 \) \[ 4(5) + 6 = 20 + 6 = 26 \quad \text{(False)} \]
The only equation that holds true when \( x = 5 \) is:
Answer: \( 4x + 9 = 29 \)