Let's first solve the given equation:
\[ x - 12 = 40 \]
To find \( x \), we can add 12 to both sides of the equation:
\[ x = 40 + 12 \] \[ x = 52 \]
Now, let's check each of the options to see which one also has \( x = 52 \) as a solution.
A. \( 12 - x = 40 \)
Rearranging gives: \[ -x = 40 - 12 \] \[ -x = 28 \] \[ x = -28 \] (not equal to 52)
B. \( \frac{x}{4} = 13 \)
Multiplying both sides by 4 gives: \[ x = 13 \times 4 \] \[ x = 52 \] (this is a match)
C. \( \frac{x}{2} = 14 \)
Multiplying both sides by 2 gives: \[ x = 14 \times 2 \] \[ x = 28 \] (not equal to 52)
D. \( x + 12 = -40 \)
Rearranging gives: \[ x = -40 - 12 \] \[ x = -52 \] (not equal to 52)
The only equation that has the same solution as the original equation \( x - 12 = 40 \) is:
B. x/4 = 13