To solve the original equation \( x - 12 = 40 \), we can add 12 to both sides:
\[ x - 12 + 12 = 40 + 12 \] \[ x = 52 \]
Now, we need to determine which of the given equations also has the solution \( x = 52 \).
Let's evaluate each option:
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\( x/4 = 13 \) \[ x = 13 \cdot 4 = 52 \quad \text{(This has the same solution)} \]
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\( 12 - x = 40 \) \[ -x = 40 - 12 \ -x = 28 \ x = -28 \quad \text{(Different solution)} \]
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\( x/2 = 14 \) \[ x = 14 \cdot 2 = 28 \quad \text{(Different solution)} \]
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\( x + 12 = -40 \) \[ x = -40 - 12 \ x = -52 \quad \text{(Different solution)} \]
The only equation that has the same solution \( x = 52 \) is: \[ x/4 = 13 \]
So, the answer is:
\( x/4 = 13 \)