Which equation has a different solution than the rest? (1 point)

16x=64
16x equals 64

x4=−1
Start Fraction x over 4 End Fraction equals negative 1

−12x=48
negative 12x equals 48

x−2=2

1 answer

Let's solve each equation to find their respective solutions:

  1. 16x = 64

    • Divide both sides by 16: \[ x = \frac{64}{16} = 4 \]
  2. x/4 = -1

    • Multiply both sides by 4: \[ x = -1 \times 4 = -4 \]
  3. -12x = 48

    • Divide both sides by -12: \[ x = \frac{48}{-12} = -4 \]
  4. x - 2 = 2

    • Add 2 to both sides: \[ x = 2 + 2 = 4 \]

Now, let's summarize the solutions:

  • For \( 16x = 64 \), the solution is \( x = 4 \).
  • For \( \frac{x}{4} = -1 \), the solution is \( x = -4 \).
  • For \( -12x = 48 \), the solution is \( x = -4 \).
  • For \( x - 2 = 2 \), the solution is \( x = 4 \).

The equations that yield the same solutions are:

  • \( 16x = 64 \) leads to \( x = 4 \).
  • \( -12x = 48 \) leads to \( x = -4 \).
  • \( x - 2 = 2 \) leads to \( x = 4 \).
  • \( \frac{x}{4} = -1 \) leads to \( x = -4 \).

The equation with a different solution is x/4 = -1 because it results in \( x = -4 \), while the others yield \( x = 4 \).