Which element would most likely lose electrons to form positive ions when bonding with other elements?

Question

Responses:

gallium (Ga)

iodine (I)

rubidium (Rb)

argon (Ar)

Answer 1

Rubidium (Rb) is the element that would most likely lose electrons to form positive ions when bonding with other elements. Rubidium is an alkali metal, located in Group 1 of the periodic table, and it has a single electron in its outermost shell. This makes it highly likely to lose that electron and form a positive ion (Rb⁺) during chemical reactions.

In contrast, gallium (Ga) can lose electrons but is less likely to do so compared to rubidium. Iodine (I) is more likely to gain electrons to form negative ions (I⁻), and argon (Ar) is a noble gas that typically does not form ions because it has a full valence shell.

Answer 2

Which statement about sodium chloride is correct
Responses:

The sodium atom and the chlorine atoms share electrons to form covalent bonds.

The sodium atom transfers electrons to the chlorine atoms to form covalent bonds.

The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.

The sodium atom and the chlorine atoms share electrons to form ionic bonds.

Answer 3

The correct statement about sodium chloride is:

The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.

In sodium chloride (NaCl), sodium (Na) donates one electron to chlorine (Cl), resulting in the formation of positively charged sodium ions (Na⁺) and negatively charged chloride ions (Cl⁻). The electrostatic attraction between these oppositely charged ions forms the ionic bond that holds the compound together.

Answer 4

Use the periodic table to answer the question.
Based on their locations in the periodic table, which two elements are most likely to form covalent bonds with each other?

Responses:

potassium (K) and iodine (I)

sodium (Na) and bromine (Br)

nitrogen (N) and oxygen (O)

magnesium (Mg) and sulfur (S)

Answer 5

Based on their locations in the periodic table, the two elements that are most likely to form covalent bonds with each other are:

Nitrogen (N) and oxygen (O).

Nitrogen and oxygen are both nonmetals located in the upper right section of the periodic table. Nonmetals tend to form covalent bonds by sharing electrons, making nitrogen and oxygen a good pair for covalent bonding.

In contrast:

• Potassium (K) is a metal that typically forms ionic bonds, not covalent bonds.
• Sodium (Na) is also a metal and would form ionic bonds with bromine (a nonmetal).
• Magnesium (Mg) is a metal that would likely form ionic bonds with sulfur (a nonmetal).

Thus, nitrogen and oxygen are the most likely to form covalent bonds.

Answer 6

Which phrase best describes electronegativity
Responses:

the relative strength with which an element attracts electrons in a chemical bond

the partial charge an element carries in a covalent or ionic bond

the number of electrons an element shares in an ionic bond

the number of electrons an element has

Answer 7

The phrase that best describes electronegativity is:

the relative strength with which an element attracts electrons in a chemical bond.

Electronegativity refers to the tendency of an atom to attract electrons towards itself when it forms a chemical bond, particularly in covalent bonding scenarios.

Answer 8

Use the table to answer the question.
Element Electronegativity
bromine 2.8
oxygen 3.5
nitrogen 3.0
phosphorus 2.1
Based on the information in the table, which pair of elements would likely form the least polar bonds with each other?
Responses:

oxygen and phosphorus

nitrogen and oxygen

phosphorus and bromine

bromine and nitrogen

Answer 9

To determine which pair of elements would likely form the least polar bonds with each other, we need to consider the difference in electronegativity values between the pairs.

1. Oxygen (3.5) and Phosphorus (2.1)

   • Difference: 3.5 - 2.1 = 1.4

2. Nitrogen (3.0) and Oxygen (3.5)

   • Difference: 3.5 - 3.0 = 0.5

3. Phosphorus (2.1) and Bromine (2.8)

   • Difference: 2.8 - 2.1 = 0.7

4. Bromine (2.8) and Nitrogen (3.0)

   • Difference: 3.0 - 2.8 = 0.2

Based on these differences, the pair of elements that would likely form the least polar bonds with each other is:

Bromine and nitrogen.

This pair has the smallest difference in electronegativity (0.2), indicating that their bond would be the least polar compared to the other combinations listed.