Responses
h=b1+b22Ah=b1+b22A
h equals Start Fraction b subscript 1 baseline plus b subscript 2 baseline over 2 upper A End Fraction
b1=2Ah−b2b1=2Ah−b2
b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline
h=12A(b1+b2)h=12A(b1+b2)
h equals Start Fraction 1 over 2 End Fraction upper A left parenthesis b subscript 1 baseline plus b subscript 2 baseline right parenthesis
h=2Ab1+b2
1 answer
The formula for the area of a trapezoid is \( A = \frac{1}{2}h(b_1 + b_2) \).
To rearrange this for \( h \):
Multiply both sides by \( 2 \) to eliminate the fraction: \[ 2A = h(b_1 + b_2) \]
Now, divide both sides by \( (b_1 + b_2) \): \[ h = \frac{2A}{b_1 + b_2} \]
So the correct response that expresses \( h \) in terms of \( A \), \( b_1 \), and \( b_2 \) is: \[ h = \frac{2A}{b_1 + b_2} \]
