Which correctly shows the area formula for a trapezoid, $A=\frac {1}{2}h(b_{1}+b_{2})$ rearranged for the

Question

quantity of interest h?(1 point)
$h=\frac {2A}{b_{1}+b_{2}}$
$h=\frac {b_{1}+b_{2}}{2A}$
$b_{1}=\frac {2A}{h}-b_{2}$
$h=\frac {1}{2}A(b_{1}+b_{2})$

Answer 1

To rearrange the area formula for a trapezoid, which is given as:

\[ A = \frac{1}{2} h (b_1 + b_2) \]

we want to solve for \( h \).

First, we can multiply both sides of the equation by 2 to eliminate the fraction:

\[ 2A = h (b_1 + b_2) \]

Next, we will isolate \( h \) by dividing both sides by \( (b_1 + b_2) \):

\[ h = \frac{2A}{b_1 + b_2} \]

Therefore, the correct rearrangement for \( h \) is:

\[ h = \frac{2A}{b_1 + b_2} \]

The correct answer is:

\(\boxed{h = \frac{2A}{b_1 + b_2}}\)