Which correctly shows the area formula for a trapezoid, A = 2h (b + bz), rearranged for the

quantity of interest h? (1 point)
01 =
2A
h
- 02
0 h = 14(01 + +b2)
0 h = b,+b2
Oh=
2A
b1+b2

1 answer

To rearrange the area formula for a trapezoid, \( A = \frac{1}{2} h (b_1 + b_2) \), for \( h \), we can follow these steps:

  1. Start with the trapezoid area formula: \[ A = \frac{1}{2} h (b_1 + b_2) \]

  2. Multiply both sides by 2 to eliminate the fraction: \[ 2A = h (b_1 + b_2) \]

  3. Divide both sides by \( (b_1 + b_2) \) to isolate \( h \): \[ h = \frac{2A}{b_1 + b_2} \]

Therefore, the correct formula for \( h \) is: \[ h = \frac{2A}{b_1 + b_2} \]

Looking at your options, the correct choice is: \[ h = \frac{2A}{b_1 + b_2} \]