(x+1)(x-3)(x-3) = 0
Three real roots
single real at x = -1
double real at x = 3
http://www.wolframalpha.com/input/?i=solve+x%5E3+-5x%5E2+%2B+3x+%2B+9+%3D+0+%3D+0
Which correctly describes the roots of the following cubic equation?
x^3-5x^2+3x+9=0
3 answers
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