which compound has the higher boiling point??

Question

1) \/^o\
2) \/\_OH


a)The compound has a larger dipole moment, resulting in more dipole-dipole interactions

b)The compound is larger in weight and size and thus has more Van der Waals interactions

c)The compound is smaller in weight and size and thus has fewer van der Waals interactions how would this affect van der waals??

d)The compound can form hydrogen bonds with itself what does this have to do with anything??

e)The compound has a less polar functional group, resulting in more van der Waals interactions

f)The compound has a smaller dipole moment, resulting in fewer dipole-dipole interactions

g) The compound has a more polar functional group, resulting in more dipole-dipole interactions

h)The compound cannot form hydrogen bonds with itself

I'm lost with this...Please help me

Answer 1

and the a,b,c,d....is for why it boils at a higher temp...I have to choose 1 but I'm totally at a loss for explanation b/c it's confusing with so many...

Help...

Answer 2

I will be happy to critique your work. In each of these, the higher bp results when some INTERmolecular force exists that makes the INTERmolecular force stronger. For instance, in the first, the OH allows a hydrogen bond to exist between molecules, thus, the bp is higher. In h, that indicates the bp is lower.